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21002141341 = 34760524903
BaseRepresentation
bin10011100011110100…
…110011111010011101
32000012200020022201201
4103203310303322131
5321003022010331
613352004435501
71342311153526
oct234364637235
960180208651
1021002141341
1189a8185705
1240a16a8b91
131c991b468c
14103342d84d
1582dc21a61
hex4e3d33e9d

21002141341 has 4 divisors (see below), whose sum is σ = 21062666592. Its totient is φ = 20941616092.

The previous prime is 21002141327. The next prime is 21002141351. The reversal of 21002141341 is 14314120012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21002141341 - 27 = 21002141213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21002141351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30262105 + ... + 30262798.

It is an arithmetic number, because the mean of its divisors is an integer number (5265666648).

Almost surely, 221002141341 is an apocalyptic number.

It is an amenable number.

21002141341 is a deficient number, since it is larger than the sum of its proper divisors (60525251).

21002141341 is an equidigital number, since it uses as much as digits as its factorization.

21002141341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60525250.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 21002141341 its reverse (14314120012), we get a palindrome (35316261353).

The spelling of 21002141341 in words is "twenty-one billion, two million, one hundred forty-one thousand, three hundred forty-one".

Divisors: 1 347 60524903 21002141341