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21002313113 = 91272301119
BaseRepresentation
bin10011100011110101…
…011101110110011001
32000012200120001100122
4103203311131312121
5321003043004423
613352012243025
71342312500365
oct234365356631
960180501318
1021002313113
1189a8292771
1240a1770475
131c99244912
1410334762a5
1582dc578c8
hex4e3d5dd99

21002313113 has 4 divisors (see below), whose sum is σ = 21004623360. Its totient is φ = 21000002868.

The previous prime is 21002313109. The next prime is 21002313121. The reversal of 21002313113 is 31131320012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21002313113 - 22 = 21002313109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21002313091 and 21002313100.

It is not an unprimeable number, because it can be changed into a prime (21002310113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1141433 + ... + 1159686.

It is an arithmetic number, because the mean of its divisors is an integer number (5251155840).

Almost surely, 221002313113 is an apocalyptic number.

It is an amenable number.

21002313113 is a deficient number, since it is larger than the sum of its proper divisors (2310247).

21002313113 is an equidigital number, since it uses as much as digits as its factorization.

21002313113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2310246.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 21002313113 its reverse (31131320012), we get a palindrome (52133633125).

The spelling of 21002313113 in words is "twenty-one billion, two million, three hundred thirteen thousand, one hundred thirteen".

Divisors: 1 9127 2301119 21002313113