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210031411101 = 3683102504349
BaseRepresentation
bin1100001110011011011…
…0001111111110011101
3202002010110011011112220
43003212312033332131
511420121020123401
6240253114015553
721113526352341
oct3034666177635
9662113134486
10210031411101
118108a28a8a6
12348571175b9
1316a626869a5
14a24649d621
1556e3e89336
hex30e6d8ff9d

210031411101 has 8 divisors (see below), whose sum is σ = 280451901600. Its totient is φ = 139815930672.

The previous prime is 210031411099. The next prime is 210031411133. The reversal of 210031411101 is 101114130012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 210031411101 - 21 = 210031411099 is a prime.

It is a super-2 number, since 2×2100314111012 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210031411171) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51250126 + ... + 51254223.

It is an arithmetic number, because the mean of its divisors is an integer number (35056487700).

Almost surely, 2210031411101 is an apocalyptic number.

It is an amenable number.

210031411101 is a deficient number, since it is larger than the sum of its proper divisors (70420490499).

210031411101 is a wasteful number, since it uses less digits than its factorization.

210031411101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102505035.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 210031411101 its reverse (101114130012), we get a palindrome (311145541113).

The spelling of 210031411101 in words is "two hundred ten billion, thirty-one million, four hundred eleven thousand, one hundred one".

Divisors: 1 3 683 2049 102504349 307513047 70010470367 210031411101