21004032240133 has 2 divisors, whose sum is σ = 21004032240134. Its totient is φ = 21004032240132.

The previous prime is 21004032240101. The next prime is 21004032240157. The reversal of 21004032240133 is 33104223040012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18883213812324 + 2120818427809 = 4345482^2 + 1456303^2 .

It is a cyclic number.

It is not a de Polignac number, because 21004032240133 - 2⁵ = 21004032240101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21004032240098 and 21004032240107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21004032240833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10502016120066 + 10502016120067.

It is an arithmetic number, because the mean of its divisors is an integer number (10502016120067).

Almost surely, 2^{21004032240133} is an apocalyptic number.

It is an amenable number.

21004032240133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21004032240133 is an equidigital number, since it uses as much as digits as its factorization.

21004032240133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 21004032240133 its reverse (33104223040012), we get a palindrome (54108255280145).

The spelling of 21004032240133 in words is "twenty-one trillion, four billion, thirty-two million, two hundred forty thousand, one hundred thirty-three".