2100414123121 has 4 divisors (see below), whose sum is σ = 2106264859200. Its totient is φ = 2094563387044.

The previous prime is 2100414123113. The next prime is 2100414123151. The reversal of 2100414123121 is 1213214140012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2100414123121 - 2³ = 2100414123113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2100414123092 and 2100414123101.

It is not an unprimeable number, because it can be changed into a prime (2100414123151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2925367501 + ... + 2925368218.

It is an arithmetic number, because the mean of its divisors is an integer number (526566214800).

Almost surely, 2^{2100414123121} is an apocalyptic number.

It is an amenable number.

2100414123121 is a deficient number, since it is larger than the sum of its proper divisors (5850736079).

2100414123121 is an equidigital number, since it uses as much as digits as its factorization.

2100414123121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5850736078.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 2100414123121 its reverse (1213214140012), we get a palindrome (3313628263133).

The spelling of 2100414123121 in words is "two trillion, one hundred billion, four hundred fourteen million, one hundred twenty-three thousand, one hundred twenty-one".