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21004301011 = 38354841517
BaseRepresentation
bin10011100011111101…
…000011001011010011
32000012211022001020111
4103203331003023103
5321004100113021
613352123022151
71342335420121
oct234375031323
960184261214
1021004301011
1189a9420261
1240a236a957
131c9978c6a5
141033832911
1582deeb8e1
hex4e3f432d3

21004301011 has 4 divisors (see below), whose sum is σ = 21059142912. Its totient is φ = 20949459112.

The previous prime is 21004300991. The next prime is 21004301029. The reversal of 21004301011 is 11010340012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21004301011 - 25 = 21004300979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21004300982 and 21004301000.

It is not an unprimeable number, because it can be changed into a prime (21004305011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27420376 + ... + 27421141.

It is an arithmetic number, because the mean of its divisors is an integer number (5264785728).

Almost surely, 221004301011 is an apocalyptic number.

21004301011 is a deficient number, since it is larger than the sum of its proper divisors (54841901).

21004301011 is an equidigital number, since it uses as much as digits as its factorization.

21004301011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54841900.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21004301011 its reverse (11010340012), we get a palindrome (32014641023).

The spelling of 21004301011 in words is "twenty-one billion, four million, three hundred one thousand, eleven".

Divisors: 1 383 54841517 21004301011