Search a number
-
+
2100433121 is a prime number
BaseRepresentation
bin111110100110010…
…0001000011100001
312102101100001120022
41331030201003201
513300202324441
6544231323225
7103023246503
oct17514410341
95371301508
102100433121
11988704546
124a7520515
13276210047
1415cd5dd73
15c460084b
hex7d3210e1

2100433121 has 2 divisors, whose sum is σ = 2100433122. Its totient is φ = 2100433120.

The previous prime is 2100433091. The next prime is 2100433129. The reversal of 2100433121 is 1213340012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1288810000 + 811623121 = 35900^2 + 28489^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2100433121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2100433121.

It is not a weakly prime, because it can be changed into another prime (2100433129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050216560 + 1050216561.

It is an arithmetic number, because the mean of its divisors is an integer number (1050216561).

Almost surely, 22100433121 is an apocalyptic number.

It is an amenable number.

2100433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100433121 is an equidigital number, since it uses as much as digits as its factorization.

2100433121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2100433121 is about 45830.4824434568. The cubic root of 2100433121 is about 1280.6671979401.

Adding to 2100433121 its reverse (1213340012), we get a palindrome (3313773133).

The spelling of 2100433121 in words is "two billion, one hundred million, four hundred thirty-three thousand, one hundred twenty-one".