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210131000113 is a prime number
BaseRepresentation
bin1100001110110011001…
…0001001101100110001
3202002101101112210222211
43003230302021230301
511420322014000423
6240311032332121
721116146013326
oct3035462115461
9662341483884
10210131000113
1181130520571
1234884544041
1316a7a1b53b8
14a2557c4b4d
1556ecaac10d
hex30ecc89b31

210131000113 has 2 divisors, whose sum is σ = 210131000114. Its totient is φ = 210131000112.

The previous prime is 210131000089. The next prime is 210131000119. The reversal of 210131000113 is 311000131012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 191403625009 + 18727375104 = 437497^2 + 136848^2 .

It is a cyclic number.

It is not a de Polignac number, because 210131000113 - 213 = 210130991921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 210131000093 and 210131000102.

It is not a weakly prime, because it can be changed into another prime (210131000119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105065500056 + 105065500057.

It is an arithmetic number, because the mean of its divisors is an integer number (105065500057).

Almost surely, 2210131000113 is an apocalyptic number.

It is an amenable number.

210131000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

210131000113 is an equidigital number, since it uses as much as digits as its factorization.

210131000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 210131000113 its reverse (311000131012), we get a palindrome (521131131125).

The spelling of 210131000113 in words is "two hundred ten billion, one hundred thirty-one million, one hundred thirteen", and thus it is an aban number.