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210133044115 = 542026608823
BaseRepresentation
bin1100001110110011100…
…1111100101110010011
3202002101112101122211121
43003230321330232103
511420323024402430
6240311144223111
721116202255451
oct3035471745623
9662345348747
10210133044115
1181131697225
123488516aa97
1316a7a74c877
14a255b979d1
1556ecd62a7a
hex30ece7cb93

210133044115 has 4 divisors (see below), whose sum is σ = 252159652944. Its totient is φ = 168106435288.

The previous prime is 210133044113. The next prime is 210133044133. The reversal of 210133044115 is 511440331012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 210133044115 - 21 = 210133044113 is a prime.

It is a super-2 number, since 2×2101330441152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 210133044115.

It is not an unprimeable number, because it can be changed into a prime (210133044113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21013304407 + ... + 21013304416.

It is an arithmetic number, because the mean of its divisors is an integer number (63039913236).

Almost surely, 2210133044115 is an apocalyptic number.

210133044115 is a deficient number, since it is larger than the sum of its proper divisors (42026608829).

210133044115 is an equidigital number, since it uses as much as digits as its factorization.

210133044115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42026608828.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 210133044115 its reverse (511440331012), we get a palindrome (721573375127).

The spelling of 210133044115 in words is "two hundred ten billion, one hundred thirty-three million, forty-four thousand, one hundred fifteen".

Divisors: 1 5 42026608823 210133044115