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21013412115 = 351400894141
BaseRepresentation
bin10011100100011111…
…110011100100010011
32000020110102221022210
4103210133303210103
5321013413141430
613353050203203
71342506025113
oct234437634423
960213387283
1021013412115
118a035835a3
1240a5423503
131c9b62c787
141034b25043
1582ebeb2b0
hex4e47f3913

21013412115 has 8 divisors (see below), whose sum is σ = 33621459408. Its totient is φ = 11207153120.

The previous prime is 21013412111. The next prime is 21013412137. The reversal of 21013412115 is 51121431012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21013412115 - 22 = 21013412111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21013412091 and 21013412100.

It is not an unprimeable number, because it can be changed into a prime (21013412111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 700447056 + ... + 700447085.

It is an arithmetic number, because the mean of its divisors is an integer number (4202682426).

Almost surely, 221013412115 is an apocalyptic number.

21013412115 is a deficient number, since it is larger than the sum of its proper divisors (12608047293).

21013412115 is a wasteful number, since it uses less digits than its factorization.

21013412115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1400894149.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 21013412115 its reverse (51121431012), we get a palindrome (72134843127).

The spelling of 21013412115 in words is "twenty-one billion, thirteen million, four hundred twelve thousand, one hundred fifteen".

Divisors: 1 3 5 15 1400894141 4202682423 7004470705 21013412115