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210140113 = 1311604123
BaseRepresentation
bin11001000011001…
…11101111010001
3112122102020001011
430201213233101
5412243440423
632504010521
75131106251
oct1441475721
9478366034
10210140113
11a8689417
125a460a41
13346c7881
141dca1961
15136adb0d
hexc867bd1

210140113 has 4 divisors (see below), whose sum is σ = 211744368. Its totient is φ = 208535860.

The previous prime is 210140107. The next prime is 210140143. The reversal of 210140113 is 311041012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 210140113 - 213 = 210131921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 210140093 and 210140102.

It is not an unprimeable number, because it can be changed into a prime (210140143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 801931 + ... + 802192.

It is an arithmetic number, because the mean of its divisors is an integer number (52936092).

Almost surely, 2210140113 is an apocalyptic number.

It is an amenable number.

210140113 is a deficient number, since it is larger than the sum of its proper divisors (1604255).

210140113 is a wasteful number, since it uses less digits than its factorization.

210140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1604254.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 210140113 is about 14496.2102978675. The cubic root of 210140113 is about 594.5243596548.

Adding to 210140113 its reverse (311041012), we get a palindrome (521181125).

The spelling of 210140113 in words is "two hundred ten million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 131 1604123 210140113