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2102002121113 is a prime number
BaseRepresentation
bin11110100101101001000…
…101101111100110011001
321102221122010211111001121
4132211221011233212121
5233414400020333423
64245351344245241
7304602400141246
oct36455105574631
97387563744047
102102002121113
117404aa442134
1229b470310821
131232aaab175b
1473a4779c5cd
1539a27d9845d
hex1e96916f999

2102002121113 has 2 divisors, whose sum is σ = 2102002121114. Its totient is φ = 2102002121112.

The previous prime is 2102002121099. The next prime is 2102002121201. The reversal of 2102002121113 is 3111212002012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2091341145609 + 10660975504 = 1446147^2 + 103252^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2102002121113 is a prime.

It is a super-2 number, since 2×21020021211132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2102072121113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1051001060556 + 1051001060557.

It is an arithmetic number, because the mean of its divisors is an integer number (1051001060557).

Almost surely, 22102002121113 is an apocalyptic number.

It is an amenable number.

2102002121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2102002121113 is an equidigital number, since it uses as much as digits as its factorization.

2102002121113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2102002121113 its reverse (3111212002012), we get a palindrome (5213214123125).

The spelling of 2102002121113 in words is "two trillion, one hundred two billion, two million, one hundred twenty-one thousand, one hundred thirteen".