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210202020131 is a prime number
BaseRepresentation
bin1100001111000100000…
…1000100100100100011
3202002120100012000010212
43003301001010210203
511420443204121011
6240322050444335
721121000455635
oct3036101044443
9662510160125
10210202020131
11811676189a4
12348a42936ab
1316a8bb2028c
14a260dd0a55
155703e3a08b
hex30f1044923

210202020131 has 2 divisors, whose sum is σ = 210202020132. Its totient is φ = 210202020130.

The previous prime is 210202020113. The next prime is 210202020163. The reversal of 210202020131 is 131020202012.

It is a happy number.

Together with previous prime (210202020113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-210202020131 is a prime.

It is a super-2 number, since 2×2102020201312 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (210202020191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105101010065 + 105101010066.

It is an arithmetic number, because the mean of its divisors is an integer number (105101010066).

Almost surely, 2210202020131 is an apocalyptic number.

210202020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

210202020131 is an equidigital number, since it uses as much as digits as its factorization.

210202020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 210202020131 its reverse (131020202012), we get a palindrome (341222222143).

The spelling of 210202020131 in words is "two hundred ten billion, two hundred two million, twenty thousand, one hundred thirty-one".