Base | Representation |
---|---|
bin | 101111110010110110000100… |
… | …001011110001001010100101 |
3 | 1000120021010122120121212201201 |
4 | 233302312010023301022211 |
5 | 210022423112300023023 |
6 | 2023021321345522501 |
7 | 62163415525366303 |
oct | 5762660413611245 |
9 | 1016233576555651 |
10 | 210202212111013 |
11 | 60a8229185a291 |
12 | 1b6aa71b643431 |
13 | 9039ca2b185a5 |
14 | 39c9bac945273 |
15 | 1947c96766bad |
hex | bf2d842f12a5 |
210202212111013 has 2 divisors, whose sum is σ = 210202212111014. Its totient is φ = 210202212111012.
The previous prime is 210202212110987. The next prime is 210202212111077. The reversal of 210202212111013 is 310111212202012.
210202212111013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 189521973823204 + 20680238287809 = 13766698^2 + 4547553^2 .
It is a cyclic number.
It is not a de Polignac number, because 210202212111013 - 241 = 208003188855461 is a prime.
It is a super-3 number, since 3×2102022121110133 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210202212111313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105101106055506 + 105101106055507.
It is an arithmetic number, because the mean of its divisors is an integer number (105101106055507).
Almost surely, 2210202212111013 is an apocalyptic number.
It is an amenable number.
210202212111013 is a deficient number, since it is larger than the sum of its proper divisors (1).
210202212111013 is an equidigital number, since it uses as much as digits as its factorization.
210202212111013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 210202212111013 its reverse (310111212202012), we get a palindrome (520313424313025).
Subtracting 210202212111013 from its reverse (310111212202012), we obtain a palindrome (99909000090999).
The spelling of 210202212111013 in words is "two hundred ten trillion, two hundred two billion, two hundred twelve million, one hundred eleven thousand, thirteen".
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