Base | Representation |
---|---|
bin | 11110100101110100111… |
… | …101001011010100111111 |
3 | 21102222011000102211200011 |
4 | 132211310331023110333 |
5 | 233420302001430413 |
6 | 4245423215244051 |
7 | 304610335250041 |
oct | 36456475132477 |
9 | 7388130384604 |
10 | 2102201201983 |
11 | 7405a1857583 |
12 | 29b506b19627 |
13 | 12331010659c |
14 | 73a65dc1a91 |
15 | 39a3a5c033d |
hex | 1e974f4b53f |
2102201201983 has 2 divisors, whose sum is σ = 2102201201984. Its totient is φ = 2102201201982.
The previous prime is 2102201201953. The next prime is 2102201202037. The reversal of 2102201201983 is 3891021022012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2102201201983 - 229 = 2101664331071 is a prime.
It is a super-4 number, since 4×21022012019834 (a number of 50 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2102201201953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1051100600991 + 1051100600992.
It is an arithmetic number, because the mean of its divisors is an integer number (1051100600992).
Almost surely, 22102201201983 is an apocalyptic number.
2102201201983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2102201201983 is an equidigital number, since it uses as much as digits as its factorization.
2102201201983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 31.
Adding to 2102201201983 its reverse (3891021022012), we get a palindrome (5993222223995).
The spelling of 2102201201983 in words is "two trillion, one hundred two billion, two hundred one million, two hundred one thousand, nine hundred eighty-three".
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