Base | Representation |
---|---|
bin | 11110100110100101011… |
… | …010001110101110010001 |
3 | 21110001020200002120122001 |
4 | 132212211122032232101 |
5 | 233423433103440213 |
6 | 4250040015114001 |
7 | 304636436054245 |
oct | 36464532165621 |
9 | 7401220076561 |
10 | 2103014124433 |
11 | 740979714212 |
12 | 29b6b3212901 |
13 | 12340c6622a1 |
14 | 73b01d52425 |
15 | 39a86b4b1dd |
hex | 1e9a568eb91 |
2103014124433 has 2 divisors, whose sum is σ = 2103014124434. Its totient is φ = 2103014124432.
The previous prime is 2103014124403. The next prime is 2103014124439. The reversal of 2103014124433 is 3344214103012.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2056551028624 + 46463095809 = 1434068^2 + 215553^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2103014124433 is a prime.
It is not a weakly prime, because it can be changed into another prime (2103014124439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1051507062216 + 1051507062217.
It is an arithmetic number, because the mean of its divisors is an integer number (1051507062217).
Almost surely, 22103014124433 is an apocalyptic number.
It is an amenable number.
2103014124433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2103014124433 is an equidigital number, since it uses as much as digits as its factorization.
2103014124433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 2103014124433 its reverse (3344214103012), we get a palindrome (5447228227445).
The spelling of 2103014124433 in words is "two trillion, one hundred three billion, fourteen million, one hundred twenty-four thousand, four hundred thirty-three".
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