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21034001113 = 81125935883
BaseRepresentation
bin10011100101101110…
…010110001011011001
32000021220011222010021
4103211232112023121
5321034201013423
613355103350441
71343146026256
oct234556261331
960256158107
1021034001113
118a141663a4
1240b02b2421
131ca298b008
14103776442d
1583191695d
hex4e5b962d9

21034001113 has 4 divisors (see below), whose sum is σ = 21059937808. Its totient is φ = 21008064420.

The previous prime is 21034001069. The next prime is 21034001119. The reversal of 21034001113 is 31110043012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21034001113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21034001119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12967131 + ... + 12968752.

It is an arithmetic number, because the mean of its divisors is an integer number (5264984452).

Almost surely, 221034001113 is an apocalyptic number.

It is an amenable number.

21034001113 is a deficient number, since it is larger than the sum of its proper divisors (25936695).

21034001113 is an equidigital number, since it uses as much as digits as its factorization.

21034001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25936694.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 21034001113 its reverse (31110043012), we get a palindrome (52144044125).

The spelling of 21034001113 in words is "twenty-one billion, thirty-four million, one thousand, one hundred thirteen".

Divisors: 1 811 25935883 21034001113