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210413134235 = 542082626847
BaseRepresentation
bin1100001111110110011…
…0011010000110011011
3202010010001102201020202
43003331212122012123
511421411230243420
6240355031412415
721126143062643
oct3037546320633
9663101381222
10210413134235
1181265802067
1234942b2410b
1316ac3799275
14a281067523
15571773c575
hex30fd99a19b

210413134235 has 4 divisors (see below), whose sum is σ = 252495761088. Its totient is φ = 168330507384.

The previous prime is 210413134219. The next prime is 210413134277. The reversal of 210413134235 is 532431314012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 210413134235 - 24 = 210413134219 is a prime.

It is a super-2 number, since 2×2104131342352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 210413134198 and 210413134207.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21041313419 + ... + 21041313428.

It is an arithmetic number, because the mean of its divisors is an integer number (63123940272).

Almost surely, 2210413134235 is an apocalyptic number.

210413134235 is a deficient number, since it is larger than the sum of its proper divisors (42082626853).

210413134235 is an equidigital number, since it uses as much as digits as its factorization.

210413134235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42082626852.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 210413134235 its reverse (532431314012), we get a palindrome (742844448247).

The spelling of 210413134235 in words is "two hundred ten billion, four hundred thirteen million, one hundred thirty-four thousand, two hundred thirty-five".

Divisors: 1 5 42082626847 210413134235