Base | Representation |
---|---|
bin | 1100001111110110011… |
… | …0011010000110011011 |
3 | 202010010001102201020202 |
4 | 3003331212122012123 |
5 | 11421411230243420 |
6 | 240355031412415 |
7 | 21126143062643 |
oct | 3037546320633 |
9 | 663101381222 |
10 | 210413134235 |
11 | 81265802067 |
12 | 34942b2410b |
13 | 16ac3799275 |
14 | a281067523 |
15 | 571773c575 |
hex | 30fd99a19b |
210413134235 has 4 divisors (see below), whose sum is σ = 252495761088. Its totient is φ = 168330507384.
The previous prime is 210413134219. The next prime is 210413134277. The reversal of 210413134235 is 532431314012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 210413134235 - 24 = 210413134219 is a prime.
It is a super-2 number, since 2×2104131342352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 210413134198 and 210413134207.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21041313419 + ... + 21041313428.
It is an arithmetic number, because the mean of its divisors is an integer number (63123940272).
Almost surely, 2210413134235 is an apocalyptic number.
210413134235 is a deficient number, since it is larger than the sum of its proper divisors (42082626853).
210413134235 is an equidigital number, since it uses as much as digits as its factorization.
210413134235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42082626852.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 210413134235 its reverse (532431314012), we get a palindrome (742844448247).
The spelling of 210413134235 in words is "two hundred ten billion, four hundred thirteen million, one hundred thirty-four thousand, two hundred thirty-five".
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