Search a number
-
+
21043000131 = 311815939317
BaseRepresentation
bin10011100110010000…
…101011001101000011
32000022112010011110020
4103212100223031003
5321044002001011
613400024304523
71343315356416
oct234620531503
960275104406
1021043000131
118a192524aa
1240b3312143
131ca47bc08a
141038a27b7d
158325e3006
hex4e642b343

21043000131 has 8 divisors (see below), whose sum is σ = 28081095504. Its totient is φ = 14016785760.

The previous prime is 21043000103. The next prime is 21043000141. The reversal of 21043000131 is 13100034012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21043000131 - 211 = 21042998083 is a prime.

It is a super-2 number, since 2×210430001312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21043000131.

It is not an unprimeable number, because it can be changed into a prime (21043000141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2966116 + ... + 2973201.

It is an arithmetic number, because the mean of its divisors is an integer number (3510136938).

Almost surely, 221043000131 is an apocalyptic number.

21043000131 is a deficient number, since it is larger than the sum of its proper divisors (7038095373).

21043000131 is a wasteful number, since it uses less digits than its factorization.

21043000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5940501.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 21043000131 its reverse (13100034012), we get a palindrome (34143034143).

The spelling of 21043000131 in words is "twenty-one billion, forty-three million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 3 1181 3543 5939317 17817951 7014333377 21043000131