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21044301433 is a prime number
BaseRepresentation
bin10011100110010101…
…101000111001111001
32000022121120021111121
4103212111220321321
5321044320121213
613400112225241
71343332416331
oct234625507171
960277507447
1021044301433
118a19a61161
1240b383b221
131ca4b5648c
141038c860c1
1583279d88d
hex4e6568e79

21044301433 has 2 divisors, whose sum is σ = 21044301434. Its totient is φ = 21044301432.

The previous prime is 21044301431. The next prime is 21044301457. The reversal of 21044301433 is 33410344012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19090396224 + 1953905209 = 138168^2 + 44203^2 .

It is a cyclic number.

It is not a de Polignac number, because 21044301433 - 21 = 21044301431 is a prime.

Together with 21044301431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 21044301398 and 21044301407.

It is not a weakly prime, because it can be changed into another prime (21044301431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10522150716 + 10522150717.

It is an arithmetic number, because the mean of its divisors is an integer number (10522150717).

Almost surely, 221044301433 is an apocalyptic number.

It is an amenable number.

21044301433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21044301433 is an equidigital number, since it uses as much as digits as its factorization.

21044301433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 21044301433 its reverse (33410344012), we get a palindrome (54454645445).

The spelling of 21044301433 in words is "twenty-one billion, forty-four million, three hundred one thousand, four hundred thirty-three".