Base | Representation |
---|---|
bin | 11110100111111001111… |
… | …011100010101010000111 |
3 | 21110011220111100101101121 |
4 | 132213321323202222013 |
5 | 233434334112033413 |
6 | 4250432432134411 |
7 | 305016535034152 |
oct | 36477173425207 |
9 | 7404814311347 |
10 | 2104432142983 |
11 | 74153709a575 |
12 | 29ba2a097407 |
13 | 1235a737c311 |
14 | 73bd83d4c99 |
15 | 39b1b39eb8d |
hex | 1e9f9ee2a87 |
2104432142983 has 2 divisors, whose sum is σ = 2104432142984. Its totient is φ = 2104432142982.
The previous prime is 2104432142971. The next prime is 2104432143019. The reversal of 2104432142983 is 3892412344012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2104432142983 - 217 = 2104432011911 is a prime.
It is a super-2 number, since 2×21044321429832 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2104432142933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052216071491 + 1052216071492.
It is an arithmetic number, because the mean of its divisors is an integer number (1052216071492).
Almost surely, 22104432142983 is an apocalyptic number.
2104432142983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104432142983 is an equidigital number, since it uses as much as digits as its factorization.
2104432142983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 331776, while the sum is 43.
Adding to 2104432142983 its reverse (3892412344012), we get a palindrome (5996844486995).
The spelling of 2104432142983 in words is "two trillion, one hundred four billion, four hundred thirty-two million, one hundred forty-two thousand, nine hundred eighty-three".
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