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2104434127 is a prime number
BaseRepresentation
bin111110101101111…
…0001110111001111
312102122212022220201
41331123301313033
513302213343002
6544453154331
7103102252315
oct17533616717
95378768821
102104434127
1198a997564
124a892b9a7
13276cb11c3
1415d6c20b5
15c4b41087
hex7d6f1dcf

2104434127 has 2 divisors, whose sum is σ = 2104434128. Its totient is φ = 2104434126.

The previous prime is 2104434083. The next prime is 2104434133. The reversal of 2104434127 is 7214344012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2104434127 - 219 = 2103909839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2104434095 and 2104434104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2104534127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052217063 + 1052217064.

It is an arithmetic number, because the mean of its divisors is an integer number (1052217064).

Almost surely, 22104434127 is an apocalyptic number.

2104434127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2104434127 is an equidigital number, since it uses as much as digits as its factorization.

2104434127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 28.

The square root of 2104434127 is about 45874.1117298199. Note that the first 3 decimals coincide. The cubic root of 2104434127 is about 1281.4798409893.

Adding to 2104434127 its reverse (7214344012), we get a palindrome (9318778139).

The spelling of 2104434127 in words is "two billion, one hundred four million, four hundred thirty-four thousand, one hundred twenty-seven".