Base | Representation |
---|---|
bin | 111110101111111… |
… | …1110101111001001 |
3 | 12102201221021121211 |
4 | 1331133332233021 |
5 | 13303004113213 |
6 | 544532533121 |
7 | 103114520161 |
oct | 17537765711 |
9 | 5381837554 |
10 | 2105535433 |
11 | 990579a31 |
12 | 4a91811a1 |
13 | 2772a8571 |
14 | 15d8cb5a1 |
15 | c4cac53d |
hex | 7d7febc9 |
2105535433 has 2 divisors, whose sum is σ = 2105535434. Its totient is φ = 2105535432.
The previous prime is 2105535427. The next prime is 2105535457. The reversal of 2105535433 is 3345355012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2078630464 + 26904969 = 45592^2 + 5187^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2105535433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2105535395 and 2105535404.
It is not a weakly prime, because it can be changed into another prime (2105530433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052767716 + 1052767717.
It is an arithmetic number, because the mean of its divisors is an integer number (1052767717).
Almost surely, 22105535433 is an apocalyptic number.
It is an amenable number.
2105535433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2105535433 is an equidigital number, since it uses as much as digits as its factorization.
2105535433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 31.
The square root of 2105535433 is about 45886.1137273576. The cubic root of 2105535433 is about 1281.7033460954.
The spelling of 2105535433 in words is "two billion, one hundred five million, five hundred thirty-five thousand, four hundred thirty-three".
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