Base | Representation |
---|---|
bin | 11110101101000110011… |
… | …101010110000100001101 |
3 | 21110201022022000201101112 |
4 | 132231012131112010031 |
5 | 234032300311240023 |
6 | 4253154203221405 |
7 | 305305016626112 |
oct | 36550635260415 |
9 | 7421268021345 |
10 | 2110011040013 |
11 | 74393a251478 |
12 | 2a0b26517865 |
13 | 123c86128316 |
14 | 741a7308909 |
15 | 39d46056478 |
hex | 1eb4675610d |
2110011040013 has 2 divisors, whose sum is σ = 2110011040014. Its totient is φ = 2110011040012.
The previous prime is 2110011040003. The next prime is 2110011040043. The reversal of 2110011040013 is 3100401100112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1063895291209 + 1046115748804 = 1031453^2 + 1022798^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110011040013 - 28 = 2110011039757 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2110011040013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110011040003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055005520006 + 1055005520007.
It is an arithmetic number, because the mean of its divisors is an integer number (1055005520007).
Almost surely, 22110011040013 is an apocalyptic number.
It is an amenable number.
2110011040013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110011040013 is an equidigital number, since it uses as much as digits as its factorization.
2110011040013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2110011040013 its reverse (3100401100112), we get a palindrome (5210412140125).
The spelling of 2110011040013 in words is "two trillion, one hundred ten billion, eleven million, forty thousand, thirteen".
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