Base | Representation |
---|---|
bin | 1001100110000110000100… |
… | …00000000001000010101010 |
3 | 2202201011010121221101210020 |
4 | 10303003002000001002222 |
5 | 10231201033320021442 |
6 | 112513133502501310 |
7 | 4305301664651220 |
oct | 463030200010252 |
9 | 82634117841706 |
10 | 21100134142122 |
11 | 67a5575709a92 |
12 | 2449420294836 |
13 | ba0970ac7c39 |
14 | 52d375482b10 |
15 | 268ce24d29ec |
hex | 1330c20010aa |
21100134142122 has 64 divisors (see below), whose sum is σ = 50370363924480. Its totient is φ = 5761388375424.
The previous prime is 21100134142093. The next prime is 21100134142159. The reversal of 21100134142122 is 22124143100112.
It is a super-3 number, since 3×211001341421223 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21100134142092 and 21100134142101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8582898 + ... + 10764125.
It is an arithmetic number, because the mean of its divisors is an integer number (787036936320).
Almost surely, 221100134142122 is an apocalyptic number.
21100134142122 is an abundant number, since it is smaller than the sum of its proper divisors (29270229782358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21100134142122 is a wasteful number, since it uses less digits than its factorization.
21100134142122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19348187.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 21100134142122 its reverse (22124143100112), we get a palindrome (43224277242234).
The spelling of 21100134142122 in words is "twenty-one trillion, one hundred billion, one hundred thirty-four million, one hundred forty-two thousand, one hundred twenty-two".
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