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211002153 = 370334051
BaseRepresentation
bin11001001001110…
…10001100101001
3112201001000112120
430210322030221
5413004032103
632534301453
75141326425
oct1444721451
9481030476
10211002153
11a911804a
125a7b7889
133493a05b
1420047b85
15137ce253
hexc93a329

211002153 has 4 divisors (see below), whose sum is σ = 281336208. Its totient is φ = 140668100.

The previous prime is 211002149. The next prime is 211002167. The reversal of 211002153 is 351200112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211002153 - 22 = 211002149 is a prime.

It is not an unprimeable number, because it can be changed into a prime (211002053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35167023 + ... + 35167028.

It is an arithmetic number, because the mean of its divisors is an integer number (70334052).

Almost surely, 2211002153 is an apocalyptic number.

It is an amenable number.

211002153 is a deficient number, since it is larger than the sum of its proper divisors (70334055).

211002153 is an equidigital number, since it uses as much as digits as its factorization.

211002153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70334054.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 211002153 is about 14525.9131554612. The cubic root of 211002153 is about 595.3362061956.

Adding to 211002153 its reverse (351200112), we get a palindrome (562202265).

The spelling of 211002153 in words is "two hundred eleven million, two thousand, one hundred fifty-three".

Divisors: 1 3 70334051 211002153