Base | Representation |
---|---|
bin | 1100010010000010110… |
… | …1100001000010001011 |
3 | 202011122002212100211211 |
4 | 3010200231201002023 |
5 | 11424113030401303 |
6 | 240533313233551 |
7 | 21146555052304 |
oct | 3044055410213 |
9 | 664562770754 |
10 | 211002200203 |
11 | 81538272043 |
12 | 34a882628b7 |
13 | 16b88837102 |
14 | a2d93a57ab |
15 | 574e2ea66d |
hex | 3120b6108b |
211002200203 has 2 divisors, whose sum is σ = 211002200204. Its totient is φ = 211002200202.
The previous prime is 211002200141. The next prime is 211002200209. The reversal of 211002200203 is 302002200112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211002200203 - 221 = 211000103051 is a prime.
It is not a weakly prime, because it can be changed into another prime (211002200209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105501100101 + 105501100102.
It is an arithmetic number, because the mean of its divisors is an integer number (105501100102).
Almost surely, 2211002200203 is an apocalyptic number.
211002200203 is a deficient number, since it is larger than the sum of its proper divisors (1).
211002200203 is an equidigital number, since it uses as much as digits as its factorization.
211002200203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 211002200203 its reverse (302002200112), we get a palindrome (513004400315).
Subtracting 211002200203 from its reverse (302002200112), we obtain a palindrome (90999999909).
The spelling of 211002200203 in words is "two hundred eleven billion, two million, two hundred thousand, two hundred three".
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