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21100347878681 is a prime number
BaseRepresentation
bin1001100110000110011101…
…01111010110110100011001
32202201011200112010100020002
410303003032233112310121
510231202003024104211
6112513211015542345
74305310201456661
oct463031657266431
982634615110202
1021100347878681
1167a5675324475
12244947b98a9b5
13ba09a6181786
1452d3959dd1a1
15268d0615203b
hex1330cebd6d19

21100347878681 has 2 divisors, whose sum is σ = 21100347878682. Its totient is φ = 21100347878680.

The previous prime is 21100347878647. The next prime is 21100347878683. The reversal of 21100347878681 is 18687874300112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12281134758025 + 8819213120656 = 3504445^2 + 2969716^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21100347878681 is a prime.

It is a super-2 number, since 2×211003478786812 (a number of 27 digits) contains 22 as substring.

Together with 21100347878683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21100347878683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550173939340 + 10550173939341.

It is an arithmetic number, because the mean of its divisors is an integer number (10550173939341).

Almost surely, 221100347878681 is an apocalyptic number.

It is an amenable number.

21100347878681 is a deficient number, since it is larger than the sum of its proper divisors (1).

21100347878681 is an equidigital number, since it uses as much as digits as its factorization.

21100347878681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3612672, while the sum is 56.

The spelling of 21100347878681 in words is "twenty-one trillion, one hundred billion, three hundred forty-seven million, eight hundred seventy-eight thousand, six hundred eighty-one".