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2110053121 = 11191823011
BaseRepresentation
bin111110111000100…
…1101101100000001
312110001102210201121
41331301031230001
513310133144441
6545213432241
7103201104241
oct17561155401
95401383647
102110053121
11993085160
124aa79b681
132781ca957
14160345b21
15c53a0dd1
hex7dc4db01

2110053121 has 4 divisors (see below), whose sum is σ = 2301876144. Its totient is φ = 1918230100.

The previous prime is 2110053083. The next prime is 2110053157. The reversal of 2110053121 is 1213500112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2110053121 - 27 = 2110052993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2110053095 and 2110053104.

It is not an unprimeable number, because it can be changed into a prime (2110053191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95911495 + ... + 95911516.

It is an arithmetic number, because the mean of its divisors is an integer number (575469036).

Almost surely, 22110053121 is an apocalyptic number.

It is an amenable number.

2110053121 is a deficient number, since it is larger than the sum of its proper divisors (191823023).

2110053121 is a wasteful number, since it uses less digits than its factorization.

2110053121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191823022.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 2110053121 is about 45935.3145303262. The cubic root of 2110053121 is about 1282.6193758726.

Adding to 2110053121 its reverse (1213500112), we get a palindrome (3323553233).

The spelling of 2110053121 in words is "two billion, one hundred ten million, fifty-three thousand, one hundred twenty-one".

Divisors: 1 11 191823011 2110053121