211010021001253 has 2 divisors, whose sum is σ = 211010021001254. Its totient is φ = 211010021001252.

The previous prime is 211010021001151. The next prime is 211010021001271. The reversal of 211010021001253 is 352100120010112.

211010021001253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112385399035204 + 98624621966049 = 10601198^2 + 9930993^2 .

It is a cyclic number.

It is not a de Polignac number, because 211010021001253 - 2²¹ = 211010018904101 is a prime.

It is a super-2 number, since 2×211010021001253² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211010021001253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211010022001253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505010500626 + 105505010500627.

It is an arithmetic number, because the mean of its divisors is an integer number (105505010500627).

Almost surely, 2^{211010021001253} is an apocalyptic number.

It is an amenable number.

211010021001253 is a deficient number, since it is larger than the sum of its proper divisors (1).

211010021001253 is an equidigital number, since it uses as much as digits as its factorization.

211010021001253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 211010021001253 its reverse (352100120010112), we get a palindrome (563110141011365).

The spelling of 211010021001253 in words is "two hundred eleven trillion, ten billion, twenty-one million, one thousand, two hundred fifty-three".