Base | Representation |
---|---|
bin | 11110101101001011110… |
… | …001111101110111100111 |
3 | 21110201112112001012222102 |
4 | 132231023301331313213 |
5 | 234032441141111012 |
6 | 4253211113122315 |
7 | 305310152612453 |
oct | 36551361756747 |
9 | 7421475035872 |
10 | 2110100332007 |
11 | 743985699908 |
12 | 2a0b503b939b |
13 | 123c9b78cc15 |
14 | 741b510d663 |
15 | 39d4dce32c2 |
hex | 1eb4bc7dde7 |
2110100332007 has 2 divisors, whose sum is σ = 2110100332008. Its totient is φ = 2110100332006.
The previous prime is 2110100332001. The next prime is 2110100332019. The reversal of 2110100332007 is 7002330010112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2110100332007 - 216 = 2110100266471 is a prime.
It is a super-2 number, since 2×21101003320072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2110100332007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110100332001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055050166003 + 1055050166004.
It is an arithmetic number, because the mean of its divisors is an integer number (1055050166004).
Almost surely, 22110100332007 is an apocalyptic number.
2110100332007 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110100332007 is an equidigital number, since it uses as much as digits as its factorization.
2110100332007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 2110100332007 its reverse (7002330010112), we get a palindrome (9112430342119).
The spelling of 2110100332007 in words is "two trillion, one hundred ten billion, one hundred million, three hundred thirty-two thousand, seven".
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