Base | Representation |
---|---|
bin | 10011101001101110… |
… | …011000101010011001 |
3 | 2000110120110222010122 |
4 | 103221232120222121 |
5 | 321203341321103 |
6 | 13405502123025 |
7 | 1344622363511 |
oct | 235156305231 |
9 | 60416428118 |
10 | 21101120153 |
11 | 8a49039983 |
12 | 410a880475 |
13 | 1cb385b419 |
14 | 1042636841 |
15 | 837773b38 |
hex | 4e9b98a99 |
21101120153 has 2 divisors, whose sum is σ = 21101120154. Its totient is φ = 21101120152.
The previous prime is 21101120113. The next prime is 21101120167. The reversal of 21101120153 is 35102110112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21080716864 + 20403289 = 145192^2 + 4517^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21101120153 is a prime.
It is a super-2 number, since 2×211011201532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21101120113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550560076 + 10550560077.
It is an arithmetic number, because the mean of its divisors is an integer number (10550560077).
Almost surely, 221101120153 is an apocalyptic number.
It is an amenable number.
21101120153 is a deficient number, since it is larger than the sum of its proper divisors (1).
21101120153 is an equidigital number, since it uses as much as digits as its factorization.
21101120153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 21101120153 its reverse (35102110112), we get a palindrome (56203230265).
The spelling of 21101120153 in words is "twenty-one billion, one hundred one million, one hundred twenty thousand, one hundred fifty-three".
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