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21101120153 is a prime number
BaseRepresentation
bin10011101001101110…
…011000101010011001
32000110120110222010122
4103221232120222121
5321203341321103
613405502123025
71344622363511
oct235156305231
960416428118
1021101120153
118a49039983
12410a880475
131cb385b419
141042636841
15837773b38
hex4e9b98a99

21101120153 has 2 divisors, whose sum is σ = 21101120154. Its totient is φ = 21101120152.

The previous prime is 21101120113. The next prime is 21101120167. The reversal of 21101120153 is 35102110112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21080716864 + 20403289 = 145192^2 + 4517^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21101120153 is a prime.

It is a super-2 number, since 2×211011201532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21101120113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550560076 + 10550560077.

It is an arithmetic number, because the mean of its divisors is an integer number (10550560077).

Almost surely, 221101120153 is an apocalyptic number.

It is an amenable number.

21101120153 is a deficient number, since it is larger than the sum of its proper divisors (1).

21101120153 is an equidigital number, since it uses as much as digits as its factorization.

21101120153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 21101120153 its reverse (35102110112), we get a palindrome (56203230265).

The spelling of 21101120153 in words is "twenty-one billion, one hundred one million, one hundred twenty thousand, one hundred fifty-three".