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2110113013003 = 2518406824753
BaseRepresentation
bin11110101101001100100…
…010010101110100001011
321110201120101220111000221
4132231030202111310023
5234033002412404003
64253212245010511
7305310365446342
oct36551442256413
97421511814027
102110113013003
11743991870276
122a0b546b3a37
13123ca12acb78
14741b6a90b59
1539d4ee9a7bd
hex1eb4c895d0b

2110113013003 has 4 divisors (see below), whose sum is σ = 2118519838008. Its totient is φ = 2101706188000.

The previous prime is 2110113012919. The next prime is 2110113013007. The reversal of 2110113013003 is 3003103110112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2110113013003 - 233 = 2101523078411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2110113013007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4203412126 + ... + 4203412627.

It is an arithmetic number, because the mean of its divisors is an integer number (529629959502).

Almost surely, 22110113013003 is an apocalyptic number.

2110113013003 is a deficient number, since it is larger than the sum of its proper divisors (8406825005).

2110113013003 is an equidigital number, since it uses as much as digits as its factorization.

2110113013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8406825004.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2110113013003 its reverse (3003103110112), we get a palindrome (5113216123115).

The spelling of 2110113013003 in words is "two trillion, one hundred ten billion, one hundred thirteen million, thirteen thousand, three".

Divisors: 1 251 8406824753 2110113013003