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21101214125143 is a prime number
BaseRepresentation
bin1001100110001000000100…
…10111110100110001010111
32202201020220220010012222101
410303010002113310301113
510231210241304001033
6112513433002342531
74305340520444605
oct463040227646127
982636826105871
1021101214125143
1167a5a7a2a2239
122449681abaa47
13ba0ab378a849
1452d438a90875
15268d5721297d
hex1331025f4c57

21101214125143 has 2 divisors, whose sum is σ = 21101214125144. Its totient is φ = 21101214125142.

The previous prime is 21101214125137. The next prime is 21101214125153. The reversal of 21101214125143 is 34152141210112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21101214125143 - 25 = 21101214125111 is a prime.

It is a super-2 number, since 2×211012141251432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21101214125153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550607062571 + 10550607062572.

It is an arithmetic number, because the mean of its divisors is an integer number (10550607062572).

Almost surely, 221101214125143 is an apocalyptic number.

21101214125143 is a deficient number, since it is larger than the sum of its proper divisors (1).

21101214125143 is an equidigital number, since it uses as much as digits as its factorization.

21101214125143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 21101214125143 its reverse (34152141210112), we get a palindrome (55253355335255).

The spelling of 21101214125143 in words is "twenty-one trillion, one hundred one billion, two hundred fourteen million, one hundred twenty-five thousand, one hundred forty-three".