Base | Representation |
---|---|
bin | 1100010010000101010… |
… | …0000011100100101011 |
3 | 202011122210212122110221 |
4 | 3010201110003210223 |
5 | 11424123122200042 |
6 | 240534313550511 |
7 | 21150036661042 |
oct | 3044124034453 |
9 | 664583778427 |
10 | 211012303147 |
11 | 81542a42588 |
12 | 34a8b715437 |
13 | 16b8a963799 |
14 | a2da875559 |
15 | 5750143d67 |
hex | 312150392b |
211012303147 has 2 divisors, whose sum is σ = 211012303148. Its totient is φ = 211012303146.
The previous prime is 211012303087. The next prime is 211012303207. The reversal of 211012303147 is 741303210112.
It is a balanced prime because it is at equal distance from previous prime (211012303087) and next prime (211012303207).
It is a cyclic number.
It is not a de Polignac number, because 211012303147 - 211 = 211012301099 is a prime.
It is a super-2 number, since 2×2110123031472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211012301147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506151573 + 105506151574.
It is an arithmetic number, because the mean of its divisors is an integer number (105506151574).
Almost surely, 2211012303147 is an apocalyptic number.
211012303147 is a deficient number, since it is larger than the sum of its proper divisors (1).
211012303147 is an equidigital number, since it uses as much as digits as its factorization.
211012303147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 211012303147 its reverse (741303210112), we get a palindrome (952315513259).
The spelling of 211012303147 in words is "two hundred eleven billion, twelve million, three hundred three thousand, one hundred forty-seven".
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