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2110131401201 is a prime number
BaseRepresentation
bin11110101101001101101…
…000011111000111110001
321110201121200111200220022
4132231031220133013301
5234033022114314301
64253214143053225
7305311010653265
oct36551550370761
97421550450808
102110131401201
117439a118a62a
122a0b5a8a1215
13123ca504a765
14741b92ba0a5
1539d518cdd1b
hex1eb4da1f1f1

2110131401201 has 2 divisors, whose sum is σ = 2110131401202. Its totient is φ = 2110131401200.

The previous prime is 2110131401179. The next prime is 2110131401221. The reversal of 2110131401201 is 1021041310112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1500193830976 + 609937570225 = 1224824^2 + 780985^2 .

It is a cyclic number.

It is not a de Polignac number, because 2110131401201 - 26 = 2110131401137 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2110131401201.

It is not a weakly prime, because it can be changed into another prime (2110131401221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055065700600 + 1055065700601.

It is an arithmetic number, because the mean of its divisors is an integer number (1055065700601).

Almost surely, 22110131401201 is an apocalyptic number.

It is an amenable number.

2110131401201 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110131401201 is an equidigital number, since it uses as much as digits as its factorization.

2110131401201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 2110131401201 its reverse (1021041310112), we get a palindrome (3131172711313).

The spelling of 2110131401201 in words is "two trillion, one hundred ten billion, one hundred thirty-one million, four hundred one thousand, two hundred one".