Base | Representation |
---|---|
bin | 1001100110001001100010… |
… | …01101101100110000101011 |
3 | 2202201022221122212210200011 |
4 | 10303010301031230300223 |
5 | 10231213344000000133 |
6 | 112514042554352351 |
7 | 4305366142331224 |
oct | 463046115546053 |
9 | 82638848783604 |
10 | 21102000000043 |
11 | 67a6342965726 |
12 | 244986112b6b7 |
13 | ba0baa536391 |
14 | 52d4b11c024b |
15 | 268da11e96cd |
hex | 13313136cc2b |
21102000000043 has 2 divisors, whose sum is σ = 21102000000044. Its totient is φ = 21102000000042.
The previous prime is 21101999999959. The next prime is 21102000000047. The reversal of 21102000000043 is 34000000020112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21102000000043 is a prime.
It is not a weakly prime, because it can be changed into another prime (21102000000047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551000000021 + 10551000000022.
It is an arithmetic number, because the mean of its divisors is an integer number (10551000000022).
Almost surely, 221102000000043 is an apocalyptic number.
21102000000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
21102000000043 is an equidigital number, since it uses as much as digits as its factorization.
21102000000043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 21102000000043 its reverse (34000000020112), we get a palindrome (55102000020155).
The spelling of 21102000000043 in words is "twenty-one trillion, one hundred two billion, forty-three", and thus it is an aban number.
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