2110200000131 has 2 divisors, whose sum is σ = 2110200000132. Its totient is φ = 2110200000130.

The previous prime is 2110200000109. The next prime is 2110200000143. The reversal of 2110200000131 is 1310000020112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2110200000131 is a prime.

It is a super-2 number, since 2×2110200000131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2110200000731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055100000065 + 1055100000066.

It is an arithmetic number, because the mean of its divisors is an integer number (1055100000066).

Almost surely, 2^{2110200000131} is an apocalyptic number.

2110200000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110200000131 is an equidigital number, since it uses as much as digits as its factorization.

2110200000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 2110200000131 its reverse (1310000020112), we get a palindrome (3420200020243).

The spelling of 2110200000131 in words is "two trillion, one hundred ten billion, two hundred million, one hundred thirty-one", and thus it is an aban number.