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21102020113 = 131358144983
BaseRepresentation
bin10011101001110001…
…110100011000010001
32000110122011200122111
4103221301310120101
5321204104120423
613405533305321
71344633132346
oct235161643021
960418150574
1021102020113
118a495a4049
12410b035241
131cb3ab4c45
1410427cc7cd
158378a060d
hex4e9c74611

21102020113 has 8 divisors (see below), whose sum is σ = 21269514816. Its totient is φ = 20934622800.

The previous prime is 21102020101. The next prime is 21102020123. The reversal of 21102020113 is 31102020112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21102020113 - 229 = 20565149201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21102020093 and 21102020102.

It is not an unprimeable number, because it can be changed into a prime (21102020123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 446620 + ... + 491602.

It is an arithmetic number, because the mean of its divisors is an integer number (2658689352).

Almost surely, 221102020113 is an apocalyptic number.

It is an amenable number.

21102020113 is a deficient number, since it is larger than the sum of its proper divisors (167494703).

21102020113 is a wasteful number, since it uses less digits than its factorization.

21102020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48695.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21102020113 its reverse (31102020112), we get a palindrome (52204040225).

Subtracting 21102020113 from its reverse (31102020112), we obtain a palindrome (9999999999).

The spelling of 21102020113 in words is "twenty-one billion, one hundred two million, twenty thousand, one hundred thirteen".

Divisors: 1 131 3581 44983 469111 5892773 161084123 21102020113