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21102120113 = 47835409413
BaseRepresentation
bin10011101001110010…
…001100110010110001
32000110122100202211012
4103221302030302301
5321204120320423
613405535400305
71344634030034
oct235162146261
960418322735
1021102120113
118a49662198
12410b083095
131cb3b1b609
14104281701b
158378c0078
hex4e9c8ccb1

21102120113 has 8 divisors (see below), whose sum is σ = 21810757248. Its totient is φ = 20404302064.

The previous prime is 21102120107. The next prime is 21102120133. The reversal of 21102120113 is 31102120112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21102120113 - 216 = 21102054577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21102120133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2700806 + ... + 2708607.

It is an arithmetic number, because the mean of its divisors is an integer number (2726344656).

Almost surely, 221102120113 is an apocalyptic number.

It is an amenable number.

21102120113 is a deficient number, since it is larger than the sum of its proper divisors (708637135).

21102120113 is an equidigital number, since it uses as much as digits as its factorization.

21102120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5409543.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 21102120113 its reverse (31102120112), we get a palindrome (52204240225).

Subtracting 21102120113 from its reverse (31102120112), we obtain a palindrome (9999999999).

The spelling of 21102120113 in words is "twenty-one billion, one hundred two million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 47 83 3901 5409413 254242411 448981279 21102120113