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21102213001 = 67314958403
BaseRepresentation
bin10011101001110010…
…100011011110001001
32000110122112111020111
4103221302203132021
5321204131304001
613405541354321
71344634564612
oct235162433611
960418474214
1021102213001
118a49715a61
12410b1089a1
131cb3b5198c
14104283cc09
158378dc851
hex4e9ca3789

21102213001 has 4 divisors (see below), whose sum is σ = 21417171472. Its totient is φ = 20787254532.

The previous prime is 21102212969. The next prime is 21102213007. The reversal of 21102213001 is 10031220112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21102213001 - 25 = 21102212969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21102213007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157479135 + ... + 157479268.

It is an arithmetic number, because the mean of its divisors is an integer number (5354292868).

Almost surely, 221102213001 is an apocalyptic number.

It is an amenable number.

21102213001 is a deficient number, since it is larger than the sum of its proper divisors (314958471).

21102213001 is an equidigital number, since it uses as much as digits as its factorization.

21102213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 314958470.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21102213001 its reverse (10031220112), we get a palindrome (31133433113).

The spelling of 21102213001 in words is "twenty-one billion, one hundred two million, two hundred thirteen thousand, one".

Divisors: 1 67 314958403 21102213001