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21102301315 = 54220460263
BaseRepresentation
bin10011101001110010…
…111001000010000011
32000110122200222101101
4103221302321002003
5321204142120230
613405543315231
71344635413234
oct235162710203
960418628341
1021102301315
118a49776347
12410b14bb17
131cb3b82c34
14104286308b
15837908aca
hex4e9cb9083

21102301315 has 4 divisors (see below), whose sum is σ = 25322761584. Its totient is φ = 16881841048.

The previous prime is 21102301313. The next prime is 21102301321. The reversal of 21102301315 is 51310320112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21102301315 - 21 = 21102301313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21102301292 and 21102301301.

It is not an unprimeable number, because it can be changed into a prime (21102301313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2110230127 + ... + 2110230136.

It is an arithmetic number, because the mean of its divisors is an integer number (6330690396).

Almost surely, 221102301315 is an apocalyptic number.

21102301315 is a deficient number, since it is larger than the sum of its proper divisors (4220460269).

21102301315 is an equidigital number, since it uses as much as digits as its factorization.

21102301315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4220460268.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 21102301315 its reverse (51310320112), we get a palindrome (72412621427).

The spelling of 21102301315 in words is "twenty-one billion, one hundred two million, three hundred one thousand, three hundred fifteen".

Divisors: 1 5 4220460263 21102301315