Base | Representation |
---|---|
bin | 101111111110111001000000… |
… | …011111001101110000111111 |
3 | 1000200012021022220002000112020 |
4 | 233332321000133031300333 |
5 | 210130003422242440320 |
6 | 2024453502421211223 |
7 | 62310262152265266 |
oct | 5776710037156077 |
9 | 1020167286060466 |
10 | 211030005046335 |
11 | 61271360342712 |
12 | 1b803041860b13 |
13 | 909a075b23c07 |
14 | 3a17c9a1595dd |
15 | 195e594a1c940 |
hex | bfee407cdc3f |
211030005046335 has 32 divisors (see below), whose sum is σ = 339811509273600. Its totient is φ = 111829724886528.
The previous prime is 211030005046309. The next prime is 211030005046351. The reversal of 211030005046335 is 533640500030112.
It is not a de Polignac number, because 211030005046335 - 25 = 211030005046303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211030005046296 and 211030005046305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 46452202 + ... + 50792391.
It is an arithmetic number, because the mean of its divisors is an integer number (10619109664800).
Almost surely, 2211030005046335 is an apocalyptic number.
211030005046335 is a deficient number, since it is larger than the sum of its proper divisors (128781504227265).
211030005046335 is a wasteful number, since it uses less digits than its factorization.
211030005046335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97245527.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 211030005046335 its reverse (533640500030112), we get a palindrome (744670505076447).
The spelling of 211030005046335 in words is "two hundred eleven trillion, thirty billion, five million, forty-six thousand, three hundred thirty-five".
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