Base | Representation |
---|---|
bin | 101111111110111001011001… |
… | …100010111010001100001101 |
3 | 1000200012022102012010111021002 |
4 | 233332321121202322030031 |
5 | 210130010302403221013 |
6 | 2024454012235550045 |
7 | 62310305445516620 |
oct | 5776713142721415 |
9 | 1020168365114232 |
10 | 211030425445133 |
11 | 61271556680538 |
12 | 1b80313a5bb325 |
13 | 909a111c582b8 |
14 | 3a17cd9d0ddb7 |
15 | 195e5bb8b0358 |
hex | bfee598ba30d |
211030425445133 has 32 divisors (see below), whose sum is σ = 256300859695104. Its totient is φ = 169619118538752.
The previous prime is 211030425445127. The next prime is 211030425445171. The reversal of 211030425445133 is 331544524030112.
It is a cyclic number.
It is not a de Polignac number, because 211030425445133 - 212 = 211030425441037 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211030425448133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 137554541 + ... + 139080237.
It is an arithmetic number, because the mean of its divisors is an integer number (8009401865472).
Almost surely, 2211030425445133 is an apocalyptic number.
It is an amenable number.
211030425445133 is a deficient number, since it is larger than the sum of its proper divisors (45270434249971).
211030425445133 is a wasteful number, since it uses less digits than its factorization.
211030425445133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1529981.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 211030425445133 its reverse (331544524030112), we get a palindrome (542574949475245).
The spelling of 211030425445133 in words is "two hundred eleven trillion, thirty billion, four hundred twenty-five million, four hundred forty-five thousand, one hundred thirty-three".
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