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2110314013441 is a prime number
BaseRepresentation
bin11110101101011000100…
…001000110001100000001
321110202002102010100210121
4132231120201012030001
5234033410341412231
64253244225100241
7305315356101424
oct36553041061401
97422072110717
102110314013441
11743a85276937
122a0baba87681
13124003b2763a
14741d56539bb
1539d62951311
hex1eb58846301

2110314013441 has 2 divisors, whose sum is σ = 2110314013442. Its totient is φ = 2110314013440.

The previous prime is 2110314013391. The next prime is 2110314013529. The reversal of 2110314013441 is 1443104130112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1851787526416 + 258526487025 = 1360804^2 + 508455^2 .

It is a cyclic number.

It is not a de Polignac number, because 2110314013441 - 233 = 2101724078849 is a prime.

It is a super-2 number, since 2×21103140134412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2110314011441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055157006720 + 1055157006721.

It is an arithmetic number, because the mean of its divisors is an integer number (1055157006721).

Almost surely, 22110314013441 is an apocalyptic number.

It is an amenable number.

2110314013441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110314013441 is an equidigital number, since it uses as much as digits as its factorization.

2110314013441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2110314013441 its reverse (1443104130112), we get a palindrome (3553418143553).

The spelling of 2110314013441 in words is "two trillion, one hundred ten billion, three hundred fourteen million, thirteen thousand, four hundred forty-one".