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21103414113 = 37034471371
BaseRepresentation
bin10011101001110111…
…001000101101100001
32000110201210111212010
4103221313020231201
5321204433222423
613410023223133
71344651026445
oct235167105541
960421714763
1021103414113
118a4a366411
12410b5a7aa9
131cb41825b2
141042a72825
15837a78693
hex4e9dc8b61

21103414113 has 4 divisors (see below), whose sum is σ = 28137885488. Its totient is φ = 14068942740.

The previous prime is 21103414109. The next prime is 21103414147. The reversal of 21103414113 is 31141430112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21103414113 - 22 = 21103414109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21103414113.

It is not an unprimeable number, because it can be changed into a prime (21103414193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3517235683 + ... + 3517235688.

It is an arithmetic number, because the mean of its divisors is an integer number (7034471372).

Almost surely, 221103414113 is an apocalyptic number.

It is an amenable number.

21103414113 is a deficient number, since it is larger than the sum of its proper divisors (7034471375).

21103414113 is an equidigital number, since it uses as much as digits as its factorization.

21103414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7034471374.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 21103414113 its reverse (31141430112), we get a palindrome (52244844225).

The spelling of 21103414113 in words is "twenty-one billion, one hundred three million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 7034471371 21103414113