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211090000223 is a prime number
BaseRepresentation
bin1100010010010111110…
…0011100100101011111
3202011212020002001211102
43010211330130211133
511424303020001343
6240550131143315
721152002253114
oct3044574344537
9664766061742
10211090000223
1181582890543
1234ab1744b3b
1316ba0a9889b
14a306cdc90b
155756d903b8
hex3125f1c95f

211090000223 has 2 divisors, whose sum is σ = 211090000224. Its totient is φ = 211090000222.

The previous prime is 211090000213. The next prime is 211090000241. The reversal of 211090000223 is 322000090112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211090000223 - 210 = 211089999199 is a prime.

It is a super-2 number, since 2×2110900002232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211090000195 and 211090000204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211090000213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105545000111 + 105545000112.

It is an arithmetic number, because the mean of its divisors is an integer number (105545000112).

Almost surely, 2211090000223 is an apocalyptic number.

211090000223 is a deficient number, since it is larger than the sum of its proper divisors (1).

211090000223 is an equidigital number, since it uses as much as digits as its factorization.

211090000223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 211090000223 its reverse (322000090112), we get a palindrome (533090090335).

The spelling of 211090000223 in words is "two hundred eleven billion, ninety million, two hundred twenty-three", and thus it is an aban number.