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2111001103 is a prime number
BaseRepresentation
bin111110111010011…
…0101001000001111
312110010012222010001
41331310311020033
513310404013403
6545250025131
7103212133111
oct17564651017
95403188101
102111001103
11993672412
124aab781a7
132784702a3
141605113b1
15c54dbc1d
hex7dd3520f

2111001103 has 2 divisors, whose sum is σ = 2111001104. Its totient is φ = 2111001102.

The previous prime is 2111001083. The next prime is 2111001133. The reversal of 2111001103 is 3011001112.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111001103 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2111001103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111001133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055500551 + 1055500552.

It is an arithmetic number, because the mean of its divisors is an integer number (1055500552).

Almost surely, 22111001103 is an apocalyptic number.

2111001103 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111001103 is an equidigital number, since it uses as much as digits as its factorization.

2111001103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 2111001103 is about 45945.6320339594. The cubic root of 2111001103 is about 1282.8114275996.

Adding to 2111001103 its reverse (3011001112), we get a palindrome (5122002215).

Subtracting 2111001103 from its reverse (3011001112), we obtain a palindrome (900000009).

The spelling of 2111001103 in words is "two billion, one hundred eleven million, one thousand, one hundred three".