211100111113 has 4 divisors (see below), whose sum is σ = 211272720768. Its totient is φ = 210927501460.

The previous prime is 211100111063. The next prime is 211100111161. The reversal of 211100111113 is 311111001112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211100111113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211100111093 and 211100111102.

It is not an unprimeable number, because it can be changed into a prime (211100117113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86302993 + ... + 86305438.

It is an arithmetic number, because the mean of its divisors is an integer number (52818180192).

Almost surely, 2^211100111113 is an apocalyptic number.

It is an amenable number.

211100111113 is a deficient number, since it is larger than the sum of its proper divisors (172609655).

211100111113 is a wasteful number, since it uses less digits than its factorization.

211100111113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172609654.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 211100111113 its reverse (311111001112), we get a palindrome (522211112225).

The spelling of 211100111113 in words is "two hundred eleven billion, one hundred million, one hundred eleven thousand, one hundred thirteen".