Base | Representation |
---|---|
bin | 11110101110000001100… |
… | …001101000100100110111 |
3 | 21110210212100201201120121 |
4 | 132232001201220210313 |
5 | 234041313004121101 |
6 | 4253440403312411 |
7 | 305341412052043 |
oct | 36560141504467 |
9 | 7423770651517 |
10 | 2111002020151 |
11 | 7442a8674522 |
12 | 2a116237b707 |
13 | 1240b3527abb |
14 | 7425cb89023 |
15 | 39da30550a1 |
hex | 1eb81868937 |
2111002020151 has 2 divisors, whose sum is σ = 2111002020152. Its totient is φ = 2111002020150.
The previous prime is 2111002020041. The next prime is 2111002020203. The reversal of 2111002020151 is 1510202001112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111002020151 - 217 = 2111001889079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111002060151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055501010075 + 1055501010076.
It is an arithmetic number, because the mean of its divisors is an integer number (1055501010076).
Almost surely, 22111002020151 is an apocalyptic number.
2111002020151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111002020151 is an equidigital number, since it uses as much as digits as its factorization.
2111002020151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 2111002020151 its reverse (1510202001112), we get a palindrome (3621204021263).
The spelling of 2111002020151 in words is "two trillion, one hundred eleven billion, two million, twenty thousand, one hundred fifty-one".
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